Base | Representation |
---|---|
bin | 11110111001011001010… |
… | …111101000110101111101 |
3 | 21111222101101020121010101 |
4 | 132321121113220311331 |
5 | 234241320040304203 |
6 | 4303220215441101 |
7 | 306253126351402 |
oct | 36713127506575 |
9 | 7458341217111 |
10 | 2123213213053 |
11 | 7494a4563489 |
12 | 2a35ab986191 |
13 | 1252ab36542a |
14 | 74a9a8602a9 |
15 | 3a36a0e141d |
hex | 1ee595e8d7d |
2123213213053 has 2 divisors, whose sum is σ = 2123213213054. Its totient is φ = 2123213213052.
The previous prime is 2123213213003. The next prime is 2123213213063. The reversal of 2123213213053 is 3503123123212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2115517888324 + 7695324729 = 1454482^2 + 87723^2 .
It is a cyclic number.
It is not a de Polignac number, because 2123213213053 - 217 = 2123213081981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2123213213003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061606606526 + 1061606606527.
It is an arithmetic number, because the mean of its divisors is an integer number (1061606606527).
Almost surely, 22123213213053 is an apocalyptic number.
It is an amenable number.
2123213213053 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123213213053 is an equidigital number, since it uses as much as digits as its factorization.
2123213213053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 2123213213053 its reverse (3503123123212), we get a palindrome (5626336336265).
The spelling of 2123213213053 in words is "two trillion, one hundred twenty-three billion, two hundred thirteen million, two hundred thirteen thousand, fifty-three".
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