Base | Representation |
---|---|
bin | 1001101001111100010000… |
… | …11111011111100001101111 |
3 | 2210011210022102100101112221 |
4 | 10310332020133133201233 |
5 | 10240332234201113403 |
6 | 113053553504540211 |
7 | 4320661342163602 |
oct | 464761037374157 |
9 | 83153272311487 |
10 | 21232313301103 |
11 | 6846634373553 |
12 | 246ab6a921667 |
13 | bb02772b4c48 |
14 | 535914122339 |
15 | 26c47b7e7dbd |
hex | 134f887df86f |
21232313301103 has 2 divisors, whose sum is σ = 21232313301104. Its totient is φ = 21232313301102.
The previous prime is 21232313301091. The next prime is 21232313301127. The reversal of 21232313301103 is 30110331323212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21232313301103 - 25 = 21232313301071 is a prime.
It is a super-2 number, since 2×212323133011032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21232313311103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10616156650551 + 10616156650552.
It is an arithmetic number, because the mean of its divisors is an integer number (10616156650552).
Almost surely, 221232313301103 is an apocalyptic number.
21232313301103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21232313301103 is an equidigital number, since it uses as much as digits as its factorization.
21232313301103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 21232313301103 its reverse (30110331323212), we get a palindrome (51342644624315).
The spelling of 21232313301103 in words is "twenty-one trillion, two hundred thirty-two billion, three hundred thirteen million, three hundred one thousand, one hundred three".
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