Base | Representation |
---|---|
bin | 1001101010001110111000… |
… | …11101011011011110011111 |
3 | 2210012202010020121221210002 |
4 | 10311013130131123132133 |
5 | 10241013223331342314 |
6 | 113102330003204515 |
7 | 4321464202436666 |
oct | 465073435333637 |
9 | 83182106557702 |
10 | 21242311980959 |
11 | 684a8a5366733 |
12 | 2470a9b37673b |
13 | bb11ab92c564 |
14 | 5361c201dddd |
15 | 26c8644e4ade |
hex | 1351dc75b79f |
21242311980959 has 2 divisors, whose sum is σ = 21242311980960. Its totient is φ = 21242311980958.
The previous prime is 21242311980949. The next prime is 21242311980961. The reversal of 21242311980959 is 95908911324212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21242311980959 - 216 = 21242311915423 is a prime.
It is a super-3 number, since 3×212423119809593 (a number of 41 digits) contains 333 as substring.
Together with 21242311980961, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21242311980949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10621155990479 + 10621155990480.
It is an arithmetic number, because the mean of its divisors is an integer number (10621155990480).
Almost surely, 221242311980959 is an apocalyptic number.
21242311980959 is a deficient number, since it is larger than the sum of its proper divisors (1).
21242311980959 is an equidigital number, since it uses as much as digits as its factorization.
21242311980959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 56.
The spelling of 21242311980959 in words is "twenty-one trillion, two hundred forty-two billion, three hundred eleven million, nine hundred eighty thousand, nine hundred fifty-nine".
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