Base | Representation |
---|---|
bin | 1100010111110100111… |
… | …1111000011100000101 |
3 | 202022122022012011210202 |
4 | 3011331033320130011 |
5 | 11440303001302322 |
6 | 241351333100245 |
7 | 21233206151225 |
oct | 3057517703405 |
9 | 668568164722 |
10 | 212554712837 |
11 | 82164659835 |
12 | 35240187685 |
13 | 1707538433c |
14 | a405658085 |
15 | 57e0769292 |
hex | 317d3f8705 |
212554712837 has 2 divisors, whose sum is σ = 212554712838. Its totient is φ = 212554712836.
The previous prime is 212554712771. The next prime is 212554712861. The reversal of 212554712837 is 738217455212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 188676428161 + 23878284676 = 434369^2 + 154526^2 .
It is a cyclic number.
It is not a de Polignac number, because 212554712837 - 28 = 212554712581 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212554712791 and 212554712800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212554742837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106277356418 + 106277356419.
It is an arithmetic number, because the mean of its divisors is an integer number (106277356419).
Almost surely, 2212554712837 is an apocalyptic number.
It is an amenable number.
212554712837 is a deficient number, since it is larger than the sum of its proper divisors (1).
212554712837 is an equidigital number, since it uses as much as digits as its factorization.
212554712837 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 940800, while the sum is 47.
The spelling of 212554712837 in words is "two hundred twelve billion, five hundred fifty-four million, seven hundred twelve thousand, eight hundred thirty-seven".
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