Base | Representation |
---|---|
bin | 1100011001100010010… |
… | …0000111010001010100 |
3 | 202100211020112122101112 |
4 | 3012120210013101110 |
5 | 11442222312020200 |
6 | 241505023514152 |
7 | 21250442431211 |
oct | 3063044072124 |
9 | 670736478345 |
10 | 213013001300 |
11 | 8237a316730 |
12 | 35349758958 |
13 | 171192c3848 |
14 | a44a472b08 |
15 | 581aae3535 |
hex | 3198907454 |
213013001300 has 72 divisors (see below), whose sum is σ = 504334512192. Its totient is φ = 77447808000.
The previous prime is 213013001281. The next prime is 213013001323. The reversal of 213013001300 is 3100310312.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11984420 + ... + 12002180.
Almost surely, 2213013001300 is an apocalyptic number.
213013001300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213013001300 is an abundant number, since it is smaller than the sum of its proper divisors (291321510892).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213013001300 is a wasteful number, since it uses less digits than its factorization.
213013001300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28689 (or 28682 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 213013001300 its reverse (3100310312), we get a palindrome (216113311612).
The spelling of 213013001300 in words is "two hundred thirteen billion, thirteen million, one thousand, three hundred".
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