Base | Representation |
---|---|
bin | 1100011001100010100… |
… | …0110110000000110011 |
3 | 202100211022212122101121 |
4 | 3012120220312000303 |
5 | 11442223121210311 |
6 | 241505110243111 |
7 | 21250456114363 |
oct | 3063050660063 |
9 | 670738778347 |
10 | 213014241331 |
11 | 8237aa93351 |
12 | 3534a056497 |
13 | 171196390a8 |
14 | a44a6b69a3 |
15 | 581ac8ab71 |
hex | 3198a36033 |
213014241331 has 2 divisors, whose sum is σ = 213014241332. Its totient is φ = 213014241330.
The previous prime is 213014241329. The next prime is 213014241487. The reversal of 213014241331 is 133142410312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213014241331 - 21 = 213014241329 is a prime.
It is a super-2 number, since 2×2130142413312 (a number of 23 digits) contains 22 as substring.
Together with 213014241329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 213014241296 and 213014241305.
It is not a weakly prime, because it can be changed into another prime (213014241731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106507120665 + 106507120666.
It is an arithmetic number, because the mean of its divisors is an integer number (106507120666).
Almost surely, 2213014241331 is an apocalyptic number.
213014241331 is a deficient number, since it is larger than the sum of its proper divisors (1).
213014241331 is an equidigital number, since it uses as much as digits as its factorization.
213014241331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 213014241331 its reverse (133142410312), we get a palindrome (346156651643).
The spelling of 213014241331 in words is "two hundred thirteen billion, fourteen million, two hundred forty-one thousand, three hundred thirty-one".
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