Base | Representation |
---|---|
bin | 1001101100000100000101… |
… | …01110111001011010010111 |
3 | 2210102202112012002101111221 |
4 | 10312002002232321122113 |
5 | 10243031103131320043 |
6 | 113151253230511211 |
7 | 4326152326340134 |
oct | 466020256713227 |
9 | 83382465071457 |
10 | 21305231120023 |
11 | 68745525a5114 |
12 | 248111a965507 |
13 | bb70c809ba66 |
14 | 53927046b58b |
15 | 26e2e81678ed |
hex | 136082bb9697 |
21305231120023 has 2 divisors, whose sum is σ = 21305231120024. Its totient is φ = 21305231120022.
The previous prime is 21305231119961. The next prime is 21305231120027. The reversal of 21305231120023 is 32002113250312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21305231120023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21305231120023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21305231120027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10652615560011 + 10652615560012.
It is an arithmetic number, because the mean of its divisors is an integer number (10652615560012).
Almost surely, 221305231120023 is an apocalyptic number.
21305231120023 is a deficient number, since it is larger than the sum of its proper divisors (1).
21305231120023 is an equidigital number, since it uses as much as digits as its factorization.
21305231120023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 21305231120023 its reverse (32002113250312), we get a palindrome (53307344370335).
The spelling of 21305231120023 in words is "twenty-one trillion, three hundred five billion, two hundred thirty-one million, one hundred twenty thousand, twenty-three".
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