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213112623388409 is a prime number
BaseRepresentation
bin110000011101001100100110…
…001101101101011011111001
31000221120100221010220111120122
4300131030212031231123321
5210413114123041412114
62033130330532103025
762613610322151323
oct6035144615553371
91027510833814518
10213112623388409
11619a4613082748
121ba9a7a2464a75
1391bb584ab5914
143a8a9c53dc613
151998835cbde8e
hexc1d32636d6f9

213112623388409 has 2 divisors, whose sum is σ = 213112623388410. Its totient is φ = 213112623388408.

The previous prime is 213112623388391. The next prime is 213112623388411. The reversal of 213112623388409 is 904883326211312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 145345399941184 + 67767223447225 = 12055928^2 + 8232085^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213112623388409 is a prime.

It is a super-3 number, since 3×2131126233884093 (a number of 44 digits) contains 333 as substring.

Together with 213112623388411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (213112623388429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556311694204 + 106556311694205.

It is an arithmetic number, because the mean of its divisors is an integer number (106556311694205).

Almost surely, 2213112623388409 is an apocalyptic number.

It is an amenable number.

213112623388409 is a deficient number, since it is larger than the sum of its proper divisors (1).

213112623388409 is an equidigital number, since it uses as much as digits as its factorization.

213112623388409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2985984, while the sum is 53.

The spelling of 213112623388409 in words is "two hundred thirteen trillion, one hundred twelve billion, six hundred twenty-three million, three hundred eighty-eight thousand, four hundred nine".