Base | Representation |
---|---|
bin | 11111000000110001010… |
… | …100010111101010110111 |
3 | 21112201211012100010022211 |
4 | 133000301110113222313 |
5 | 234404024041432411 |
6 | 4311010025434251 |
7 | 306653263222063 |
oct | 37006124275267 |
9 | 7481735303284 |
10 | 2131131202231 |
11 | 751898006999 |
12 | 2a503b63b987 |
13 | 125c708c2b25 |
14 | 7520c29aaa3 |
15 | 3a6802dc221 |
hex | 1f031517ab7 |
2131131202231 has 2 divisors, whose sum is σ = 2131131202232. Its totient is φ = 2131131202230.
The previous prime is 2131131202183. The next prime is 2131131202253. The reversal of 2131131202231 is 1322021311312.
It is an a-pointer prime, because the next prime (2131131202253) can be obtained adding 2131131202231 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2131131202231 - 217 = 2131131071159 is a prime.
It is a super-2 number, since 2×21311312022312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131131802231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065565601115 + 1065565601116.
It is an arithmetic number, because the mean of its divisors is an integer number (1065565601116).
Almost surely, 22131131202231 is an apocalyptic number.
2131131202231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131131202231 is an equidigital number, since it uses as much as digits as its factorization.
2131131202231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 2131131202231 its reverse (1322021311312), we get a palindrome (3453152513543).
The spelling of 2131131202231 in words is "two trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred two thousand, two hundred thirty-one".
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