Base | Representation |
---|---|
bin | 11111000000110001011… |
… | …100011101001100011100 |
3 | 21112201211100022211010020 |
4 | 133000301130131030130 |
5 | 234404030112301022 |
6 | 4311010143112140 |
7 | 306653320231152 |
oct | 37006134351434 |
9 | 7481740284106 |
10 | 2131133322012 |
11 | 751899224582 |
12 | 2a50402a2650 |
13 | 125c71185936 |
14 | 7520c68d3d2 |
15 | 3a6805aa35c |
hex | 1f03171d31c |
2131133322012 has 12 divisors (see below), whose sum is σ = 4972644418056. Its totient is φ = 710377774000.
The previous prime is 2131133322011. The next prime is 2131133322083. The reversal of 2131133322012 is 2102233311312.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-3 number, since 3×21311333220123 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131133322011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88797221739 + ... + 88797221762.
It is an arithmetic number, because the mean of its divisors is an integer number (414387034838).
Almost surely, 22131133322012 is an apocalyptic number.
It is an amenable number.
2131133322012 is an abundant number, since it is smaller than the sum of its proper divisors (2841511096044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131133322012 is a wasteful number, since it uses less digits than its factorization.
2131133322012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177594443508 (or 177594443506 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 2131133322012 its reverse (2102233311312), we get a palindrome (4233366633324).
The spelling of 2131133322012 in words is "two trillion, one hundred thirty-one billion, one hundred thirty-three million, three hundred twenty-two thousand, twelve".
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