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213114442397 is a prime number
BaseRepresentation
bin1100011001111010011…
…1000101001010011101
3202101002022102101102012
43012132213011022131
511442424244124042
6241523050041005
721253113604643
oct3063647051235
9671068371365
10213114442397
118242160194a
1235377719165
131713432026c
14a459b1b193
15582497ee82
hex319e9c529d

213114442397 has 2 divisors, whose sum is σ = 213114442398. Its totient is φ = 213114442396.

The previous prime is 213114442243. The next prime is 213114442399. The reversal of 213114442397 is 793244411312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 206939468836 + 6174973561 = 454906^2 + 78581^2 .

It is a cyclic number.

It is not a de Polignac number, because 213114442397 - 28 = 213114442141 is a prime.

It is a super-2 number, since 2×2131144423972 (a number of 23 digits) contains 22 as substring.

Together with 213114442399, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213114442399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106557221198 + 106557221199.

It is an arithmetic number, because the mean of its divisors is an integer number (106557221199).

Almost surely, 2213114442397 is an apocalyptic number.

It is an amenable number.

213114442397 is a deficient number, since it is larger than the sum of its proper divisors (1).

213114442397 is an equidigital number, since it uses as much as digits as its factorization.

213114442397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 145152, while the sum is 41.

The spelling of 213114442397 in words is "two hundred thirteen billion, one hundred fourteen million, four hundred forty-two thousand, three hundred ninety-seven".