Base | Representation |
---|---|
bin | 110000011101010011110111… |
… | …100111000001110111101111 |
3 | 1000221121010002022010011121212 |
4 | 300131103313213001313233 |
5 | 210413231120421244101 |
6 | 2033134101413345035 |
7 | 62614304652342326 |
oct | 6035236747016757 |
9 | 1027533068104555 |
10 | 213120431431151 |
11 | 619a795a560832 |
12 | 1baa020133817b |
13 | 91bc22a62945a |
14 | 3a8b1263b90bd |
15 | 1998b414ed1bb |
hex | c1d4f79c1def |
213120431431151 has 2 divisors, whose sum is σ = 213120431431152. Its totient is φ = 213120431431150.
The previous prime is 213120431431111. The next prime is 213120431431213. The reversal of 213120431431151 is 151134134021312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213120431431151 - 26 = 213120431431087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213120431431111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106560215715575 + 106560215715576.
It is an arithmetic number, because the mean of its divisors is an integer number (106560215715576).
Almost surely, 2213120431431151 is an apocalyptic number.
213120431431151 is a deficient number, since it is larger than the sum of its proper divisors (1).
213120431431151 is an equidigital number, since it uses as much as digits as its factorization.
213120431431151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 213120431431151 its reverse (151134134021312), we get a palindrome (364254565452463).
The spelling of 213120431431151 in words is "two hundred thirteen trillion, one hundred twenty billion, four hundred thirty-one million, four hundred thirty-one thousand, one hundred fifty-one".
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