Base | Representation |
---|---|
bin | 10011110110010011… |
… | …100110000110001101 |
3 | 2001000021122222202112 |
4 | 103312103212012031 |
5 | 322121410413401 |
6 | 13442442233405 |
7 | 1353064502042 |
oct | 236623460615 |
9 | 61007588675 |
10 | 21312201101 |
11 | 9047200144 |
12 | 41694b5865 |
13 | 20184c52a9 |
14 | 10626a11c9 |
15 | 84b06b3bb |
hex | 4f64e618d |
21312201101 has 2 divisors, whose sum is σ = 21312201102. Its totient is φ = 21312201100.
The previous prime is 21312201091. The next prime is 21312201133. The reversal of 21312201101 is 10110221312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19273768900 + 2038432201 = 138830^2 + 45149^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21312201101 is a prime.
It is a super-2 number, since 2×213122011012 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21312201151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656100550 + 10656100551.
It is an arithmetic number, because the mean of its divisors is an integer number (10656100551).
Almost surely, 221312201101 is an apocalyptic number.
It is an amenable number.
21312201101 is a deficient number, since it is larger than the sum of its proper divisors (1).
21312201101 is an equidigital number, since it uses as much as digits as its factorization.
21312201101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 21312201101 its reverse (10110221312), we get a palindrome (31422422413).
The spelling of 21312201101 in words is "twenty-one billion, three hundred twelve million, two hundred one thousand, one hundred one".
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