Base | Representation |
---|---|
bin | 110000011101010101010110… |
… | …111101101010110000000000 |
3 | 1000221121021012210100220200101 |
4 | 300131111112331222300000 |
5 | 210413242404441420110 |
6 | 2033134524242132144 |
7 | 62614362416224225 |
oct | 6035252675526000 |
9 | 1027537183326611 |
10 | 213122031201280 |
11 | 619a8600595803 |
12 | 1baa0589051054 |
13 | 91bc423bb16b6 |
14 | 3a8b238a4d94c |
15 | 1998bd6ba413a |
hex | c1d556f6ac00 |
213122031201280 has 88 divisors (see below), whose sum is σ = 511251884493840. Its totient is φ = 85247351439360.
The previous prime is 213122031201197. The next prime is 213122031201281. The reversal of 213122031201280 is 82102130221312.
It is not an unprimeable number, because it can be changed into a prime (213122031201281) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 327913435 + ... + 328562725.
Almost surely, 2213122031201280 is an apocalyptic number.
213122031201280 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213122031201280 is an abundant number, since it is smaller than the sum of its proper divisors (298129853292560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213122031201280 is an equidigital number, since it uses as much as digits as its factorization.
213122031201280 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 713425 (or 713407 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 213122031201280 its reverse (82102130221312), we get a palindrome (295224161422592).
The spelling of 213122031201280 in words is "two hundred thirteen trillion, one hundred twenty-two billion, thirty-one million, two hundred one thousand, two hundred eighty".
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