Base | Representation |
---|---|
bin | 110000011101010101101110… |
… | …001001100101101110100111 |
3 | 1000221121022012220100012220112 |
4 | 300131111232021211232213 |
5 | 210413244204032434112 |
6 | 2033135031015523235 |
7 | 62614405151536262 |
oct | 6035255611455647 |
9 | 1027538186305815 |
10 | 213122420202407 |
11 | 619a8790129041 |
12 | 1baa067738951b |
13 | 91bc486671891 |
14 | 3a8b27458dcd9 |
15 | 1998c0ade3a22 |
hex | c1d56e265ba7 |
213122420202407 has 2 divisors, whose sum is σ = 213122420202408. Its totient is φ = 213122420202406.
The previous prime is 213122420202397. The next prime is 213122420202421. The reversal of 213122420202407 is 704202024221312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213122420202407 - 28 = 213122420202151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213122420202487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106561210101203 + 106561210101204.
It is an arithmetic number, because the mean of its divisors is an integer number (106561210101204).
Almost surely, 2213122420202407 is an apocalyptic number.
213122420202407 is a deficient number, since it is larger than the sum of its proper divisors (1).
213122420202407 is an equidigital number, since it uses as much as digits as its factorization.
213122420202407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 213122420202407 its reverse (704202024221312), we get a palindrome (917324444423719).
The spelling of 213122420202407 in words is "two hundred thirteen trillion, one hundred twenty-two billion, four hundred twenty million, two hundred two thousand, four hundred seven".
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