213124414127 has 2 divisors, whose sum is σ = 213124414128. Its totient is φ = 213124414126.

The previous prime is 213124414099. The next prime is 213124414157. The reversal of 213124414127 is 721414421312.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-213124414127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 213124414093 and 213124414102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213124414157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106562207063 + 106562207064.

It is an arithmetic number, because the mean of its divisors is an integer number (106562207064).

Almost surely, 2^213124414127 is an apocalyptic number.

213124414127 is a deficient number, since it is larger than the sum of its proper divisors (1).

213124414127 is an equidigital number, since it uses as much as digits as its factorization.

213124414127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10752, while the sum is 32.

Adding to 213124414127 its reverse (721414421312), we get a palindrome (934538835439).

The spelling of 213124414127 in words is "two hundred thirteen billion, one hundred twenty-four million, four hundred fourteen thousand, one hundred twenty-seven".