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213130031 is a prime number
BaseRepresentation
bin11001011010000…
…01101100101111
3112212001010102212
430231001230233
5414030130111
633052041035
75165401232
oct1455015457
9485033385
10213130031
11aa340824
125b46317b
133520375a
142043d419
1513a9e98b
hexcb41b2f

213130031 has 2 divisors, whose sum is σ = 213130032. Its totient is φ = 213130030.

The previous prime is 213129979. The next prime is 213130033. The reversal of 213130031 is 130031312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213130031 - 214 = 213113647 is a prime.

It is a super-2 number, since 2×2131300312 = 90848820228121922, which contains 22 as substring.

Together with 213130033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 213129988 and 213130015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213130033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106565015 + 106565016.

It is an arithmetic number, because the mean of its divisors is an integer number (106565016).

Almost surely, 2213130031 is an apocalyptic number.

213130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

213130031 is an equidigital number, since it uses as much as digits as its factorization.

213130031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 213130031 is about 14598.9736283069. The cubic root of 213130031 is about 597.3307642059.

Adding to 213130031 its reverse (130031312), we get a palindrome (343161343).

The spelling of 213130031 in words is "two hundred thirteen million, one hundred thirty thousand, thirty-one".