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213134644453 is a prime number
BaseRepresentation
bin1100011001111111010…
…0001001010011100101
3202101010201102202102111
43012133310021103211
511442444432110303
6241525051041021
721253450405033
oct3063764112345
9671121382374
10213134644453
1182431a4aa65
1235382440171
1317138574643
14a45c699553
155826620b6d
hex319fd094e5

213134644453 has 2 divisors, whose sum is σ = 213134644454. Its totient is φ = 213134644452.

The previous prime is 213134644451. The next prime is 213134644559. The reversal of 213134644453 is 354446431312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130373711329 + 82760933124 = 361073^2 + 287682^2 .

It is a cyclic number.

It is not a de Polignac number, because 213134644453 - 21 = 213134644451 is a prime.

It is a super-2 number, since 2×2131346444532 (a number of 23 digits) contains 22 as substring.

Together with 213134644451, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213134644451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106567322226 + 106567322227.

It is an arithmetic number, because the mean of its divisors is an integer number (106567322227).

Almost surely, 2213134644453 is an apocalyptic number.

It is an amenable number.

213134644453 is a deficient number, since it is larger than the sum of its proper divisors (1).

213134644453 is an equidigital number, since it uses as much as digits as its factorization.

213134644453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 414720, while the sum is 40.

The spelling of 213134644453 in words is "two hundred thirteen billion, one hundred thirty-four million, six hundred forty-four thousand, four hundred fifty-three".