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21313502654413 is a prime number
BaseRepresentation
bin1001101100010011011111…
…10000010010111111001101
32210110112212122102212120111
410312021233300102333031
510243200023134420123
6113155142110320021
74326564315251554
oct466115760227715
983415778385514
1021313502654413
116878007674352
122482848ab9011
13bb7b159541c8
14539816c18d9b
1526e62e3ec90d
hex13626fc12fcd

21313502654413 has 2 divisors, whose sum is σ = 21313502654414. Its totient is φ = 21313502654412.

The previous prime is 21313502654363. The next prime is 21313502654453. The reversal of 21313502654413 is 31445620531312.

It is an a-pointer prime, because the next prime (21313502654453) can be obtained adding 21313502654413 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15863229539689 + 5450273114724 = 3982867^2 + 2334582^2 .

It is a cyclic number.

It is not a de Polignac number, because 21313502654413 - 213 = 21313502646221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21313502654453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656751327206 + 10656751327207.

It is an arithmetic number, because the mean of its divisors is an integer number (10656751327207).

Almost surely, 221313502654413 is an apocalyptic number.

It is an amenable number.

21313502654413 is a deficient number, since it is larger than the sum of its proper divisors (1).

21313502654413 is an equidigital number, since it uses as much as digits as its factorization.

21313502654413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 21313502654413 in words is "twenty-one trillion, three hundred thirteen billion, five hundred two million, six hundred fifty-four thousand, four hundred thirteen".