Base | Representation |
---|---|
bin | 1100011010000000110… |
… | …0111011101011000101 |
3 | 202101011011122212200021 |
4 | 3012200030323223011 |
5 | 11443003113022323 |
6 | 241525442215141 |
7 | 21253556546656 |
oct | 3064014735305 |
9 | 671134585607 |
10 | 213141142213 |
11 | 8243568890a |
12 | 353846544b1 |
13 | 17139a0b07c |
14 | a45d4ab52d |
15 | 5826ea605d |
hex | 31a033bac5 |
213141142213 has 2 divisors, whose sum is σ = 213141142214. Its totient is φ = 213141142212.
The previous prime is 213141142189. The next prime is 213141142217. The reversal of 213141142213 is 312241141312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122246731044 + 90894411169 = 349638^2 + 301487^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213141142213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213141142217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106570571106 + 106570571107.
It is an arithmetic number, because the mean of its divisors is an integer number (106570571107).
Almost surely, 2213141142213 is an apocalyptic number.
It is an amenable number.
213141142213 is a deficient number, since it is larger than the sum of its proper divisors (1).
213141142213 is an equidigital number, since it uses as much as digits as its factorization.
213141142213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 25.
Adding to 213141142213 its reverse (312241141312), we get a palindrome (525382283525).
Subtracting 213141142213 from its reverse (312241141312), we obtain a palindrome (99099999099).
The spelling of 213141142213 in words is "two hundred thirteen billion, one hundred forty-one million, one hundred forty-two thousand, two hundred thirteen".
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