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213141252557 is a prime number
BaseRepresentation
bin1100011010000000110…
…1010110100111001101
3202101011011212111001002
43012200031112213031
511443003130040212
6241525444430045
721253560516452
oct3064015264715
9671134774032
10213141252557
1182435753802
12353846a8325
1317139a4936c
14a45d4d9829
155826ec8ac2
hex31a03569cd

213141252557 has 2 divisors, whose sum is σ = 213141252558. Its totient is φ = 213141252556.

The previous prime is 213141252509. The next prime is 213141252593. The reversal of 213141252557 is 755252141312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196350016996 + 16791235561 = 443114^2 + 129581^2 .

It is a cyclic number.

It is not a de Polignac number, because 213141252557 - 224 = 213124475341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 213141252557.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213141222557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106570626278 + 106570626279.

It is an arithmetic number, because the mean of its divisors is an integer number (106570626279).

Almost surely, 2213141252557 is an apocalyptic number.

It is an amenable number.

213141252557 is a deficient number, since it is larger than the sum of its proper divisors (1).

213141252557 is an equidigital number, since it uses as much as digits as its factorization.

213141252557 is an evil number, because the sum of its binary digits is even.

The product of its digits is 84000, while the sum is 38.

Adding to 213141252557 its reverse (755252141312), we get a palindrome (968393393869).

The spelling of 213141252557 in words is "two hundred thirteen billion, one hundred forty-one million, two hundred fifty-two thousand, five hundred fifty-seven".