Base | Representation |
---|---|
bin | 1001101100010100101100… |
… | …11010100001111111001111 |
3 | 2210110121112211220110022202 |
4 | 10312022112122201333033 |
5 | 10243202340210310421 |
6 | 113155330320232115 |
7 | 4326616352310353 |
oct | 466122632417717 |
9 | 83417484813282 |
10 | 21314151260111 |
11 | 687830a800416 |
12 | 24829aa16b63b |
13 | bb7bba13a668 |
14 | 539879015463 |
15 | 26e66b31c10b |
hex | 1362966a1fcf |
21314151260111 has 2 divisors, whose sum is σ = 21314151260112. Its totient is φ = 21314151260110.
The previous prime is 21314151260029. The next prime is 21314151260113. The reversal of 21314151260111 is 11106215141312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21314151260111 - 210 = 21314151259087 is a prime.
Together with 21314151260113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21314151260113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657075630055 + 10657075630056.
It is an arithmetic number, because the mean of its divisors is an integer number (10657075630056).
Almost surely, 221314151260111 is an apocalyptic number.
21314151260111 is a deficient number, since it is larger than the sum of its proper divisors (1).
21314151260111 is an equidigital number, since it uses as much as digits as its factorization.
21314151260111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 29.
The spelling of 21314151260111 in words is "twenty-one trillion, three hundred fourteen billion, one hundred fifty-one million, two hundred sixty thousand, one hundred eleven".
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