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21314151260111 is a prime number
BaseRepresentation
bin1001101100010100101100…
…11010100001111111001111
32210110121112211220110022202
410312022112122201333033
510243202340210310421
6113155330320232115
74326616352310353
oct466122632417717
983417484813282
1021314151260111
11687830a800416
1224829aa16b63b
13bb7bba13a668
14539879015463
1526e66b31c10b
hex1362966a1fcf

21314151260111 has 2 divisors, whose sum is σ = 21314151260112. Its totient is φ = 21314151260110.

The previous prime is 21314151260029. The next prime is 21314151260113. The reversal of 21314151260111 is 11106215141312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21314151260111 - 210 = 21314151259087 is a prime.

Together with 21314151260113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21314151260113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657075630055 + 10657075630056.

It is an arithmetic number, because the mean of its divisors is an integer number (10657075630056).

Almost surely, 221314151260111 is an apocalyptic number.

21314151260111 is a deficient number, since it is larger than the sum of its proper divisors (1).

21314151260111 is an equidigital number, since it uses as much as digits as its factorization.

21314151260111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 29.

The spelling of 21314151260111 in words is "twenty-one trillion, three hundred fourteen billion, one hundred fifty-one million, two hundred sixty thousand, one hundred eleven".