Base | Representation |
---|---|
bin | 11111000001000010100… |
… | …101110111001001110111 |
3 | 21112202120101122101120001 |
4 | 133001002211313021313 |
5 | 234410122234002221 |
6 | 4311054501052131 |
7 | 306663412401331 |
oct | 37010245671167 |
9 | 7482511571501 |
10 | 2131421000311 |
11 | 751a26652539 |
12 | 2a51006b7047 |
13 | 125cb895b195 |
14 | 75238976451 |
15 | 3a69a983391 |
hex | 1f042977277 |
2131421000311 has 2 divisors, whose sum is σ = 2131421000312. Its totient is φ = 2131421000310.
The previous prime is 2131421000299. The next prime is 2131421000333. The reversal of 2131421000311 is 1130001241312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2131421000311 - 229 = 2130884129399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131421700311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065710500155 + 1065710500156.
It is an arithmetic number, because the mean of its divisors is an integer number (1065710500156).
Almost surely, 22131421000311 is an apocalyptic number.
2131421000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131421000311 is an equidigital number, since it uses as much as digits as its factorization.
2131421000311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2131421000311 its reverse (1130001241312), we get a palindrome (3261422241623).
The spelling of 2131421000311 in words is "two trillion, one hundred thirty-one billion, four hundred twenty-one million, three hundred eleven", and thus it is an aban number.
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