2131421000333 has 2 divisors, whose sum is σ = 2131421000334. Its totient is φ = 2131421000332.

The previous prime is 2131421000311. The next prime is 2131421000339. The reversal of 2131421000333 is 3330001241312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1192066545124 + 939354455209 = 1091818^2 + 969203^2 .

It is a cyclic number.

It is not a de Polignac number, because 2131421000333 - 2⁸ = 2131421000077 is a prime.

It is a super-2 number, since 2×2131421000333² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131421000299 and 2131421000308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131421000339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065710500166 + 1065710500167.

It is an arithmetic number, because the mean of its divisors is an integer number (1065710500167).

Almost surely, 2^{2131421000333} is an apocalyptic number.

It is an amenable number.

2131421000333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131421000333 is an equidigital number, since it uses as much as digits as its factorization.

2131421000333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2131421000333 its reverse (3330001241312), we get a palindrome (5461422241645).

The spelling of 2131421000333 in words is "two trillion, one hundred thirty-one billion, four hundred twenty-one million, three hundred thirty-three", and thus it is an aban number.