213153420125117 has 2 divisors, whose sum is σ = 213153420125118. Its totient is φ = 213153420125116.

The previous prime is 213153420125101. The next prime is 213153420125197. The reversal of 213153420125117 is 711521024351312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119672638371001 + 93480781754116 = 10939499^2 + 9668546^2 .

It is a cyclic number.

It is not a de Polignac number, because 213153420125117 - 2⁴ = 213153420125101 is a prime.

It is a super-2 number, since 2×213153420125117² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213153420125197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106576710062558 + 106576710062559.

It is an arithmetic number, because the mean of its divisors is an integer number (106576710062559).

Almost surely, 2^{213153420125117} is an apocalyptic number.

It is an amenable number.

213153420125117 is a deficient number, since it is larger than the sum of its proper divisors (1).

213153420125117 is an equidigital number, since it uses as much as digits as its factorization.

213153420125117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 38.

Adding to 213153420125117 its reverse (711521024351312), we get a palindrome (924674444476429).

The spelling of 213153420125117 in words is "two hundred thirteen trillion, one hundred fifty-three billion, four hundred twenty million, one hundred twenty-five thousand, one hundred seventeen".