Base | Representation |
---|---|
bin | 11111000001100101000… |
… | …111000000001100001111 |
3 | 21112211001202100101101211 |
4 | 133001211013000030033 |
5 | 234412314012112143 |
6 | 4311232145315251 |
7 | 310013643645625 |
oct | 37014507001417 |
9 | 7484052311354 |
10 | 2132000113423 |
11 | 7521a3534814 |
12 | 2a5242635b27 |
13 | 12607b922a6b |
14 | 75291843515 |
15 | 3a6d172749d |
hex | 1f0651c030f |
2132000113423 has 2 divisors, whose sum is σ = 2132000113424. Its totient is φ = 2132000113422.
The previous prime is 2132000113421. The next prime is 2132000113459. The reversal of 2132000113423 is 3243110002312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2132000113423 - 21 = 2132000113421 is a prime.
Together with 2132000113421, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 2132000113394 and 2132000113403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132000113421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066000056711 + 1066000056712.
It is an arithmetic number, because the mean of its divisors is an integer number (1066000056712).
Almost surely, 22132000113423 is an apocalyptic number.
2132000113423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132000113423 is an equidigital number, since it uses as much as digits as its factorization.
2132000113423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 2132000113423 its reverse (3243110002312), we get a palindrome (5375110115735).
The spelling of 2132000113423 in words is "two trillion, one hundred thirty-two billion, one hundred thirteen thousand, four hundred twenty-three".
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