Base | Representation |
---|---|
bin | 11111000001100101110… |
… | …101001001011101111111 |
3 | 21112211002121002221211221 |
4 | 133001211311021131333 |
5 | 234412330111210142 |
6 | 4311233300454211 |
7 | 310014151530016 |
oct | 37014565113577 |
9 | 7484077087757 |
10 | 2132012210047 |
11 | 7521aa347125 |
12 | 2a52466aa367 |
13 | 126081299a25 |
14 | 752932b1a7d |
15 | 3a6d2816767 |
hex | 1f065d4977f |
2132012210047 has 2 divisors, whose sum is σ = 2132012210048. Its totient is φ = 2132012210046.
The previous prime is 2132012210021. The next prime is 2132012210063. The reversal of 2132012210047 is 7400122102312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2132012210047 - 211 = 2132012207999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132012210747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066006105023 + 1066006105024.
It is an arithmetic number, because the mean of its divisors is an integer number (1066006105024).
Almost surely, 22132012210047 is an apocalyptic number.
2132012210047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132012210047 is an equidigital number, since it uses as much as digits as its factorization.
2132012210047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 2132012210047 its reverse (7400122102312), we get a palindrome (9532134312359).
The spelling of 2132012210047 in words is "two trillion, one hundred thirty-two billion, twelve million, two hundred ten thousand, forty-seven".
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