Base | Representation |
---|---|
bin | 11111000001100110111… |
… | …110000000110100011110 |
3 | 21112211010221001101121121 |
4 | 133001212332000310132 |
5 | 234412400003424014 |
6 | 4311235222121154 |
7 | 310014503063224 |
oct | 37014676006436 |
9 | 7484127041547 |
10 | 2132031311134 |
11 | 75220a10304a |
12 | 2a5250b801ba |
13 | 126085226c4a |
14 | 75295a44b14 |
15 | 3a6d433b124 |
hex | 1f066f80d1e |
2132031311134 has 8 divisors (see below), whose sum is σ = 3266090519328. Its totient is φ = 1043334471360.
The previous prime is 2132031311119. The next prime is 2132031311141. The reversal of 2132031311134 is 4311131302312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×21320313111342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2132031311099 and 2132031311108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11340591987 + ... + 11340592174.
It is an arithmetic number, because the mean of its divisors is an integer number (408261314916).
Almost surely, 22132031311134 is an apocalyptic number.
2132031311134 is a deficient number, since it is larger than the sum of its proper divisors (1134059208194).
2132031311134 is a wasteful number, since it uses less digits than its factorization.
2132031311134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22681184210.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 2132031311134 its reverse (4311131302312), we get a palindrome (6443162613446).
The spelling of 2132031311134 in words is "two trillion, one hundred thirty-two billion, thirty-one million, three hundred eleven thousand, one hundred thirty-four".
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