Base | Representation |
---|---|
bin | 1100011010010100010… |
… | …1100111101000100111 |
3 | 202101100212220022222221 |
4 | 3012211011213220213 |
5 | 11443140104024312 |
6 | 241541531133211 |
7 | 21255603353431 |
oct | 3064505475047 |
9 | 671325808887 |
10 | 213223111207 |
11 | 82477984387 |
12 | 353a7ba4207 |
13 | 171509aa732 |
14 | a46a327651 |
15 | 582e298207 |
hex | 31a5167a27 |
213223111207 has 2 divisors, whose sum is σ = 213223111208. Its totient is φ = 213223111206.
The previous prime is 213223111177. The next prime is 213223111223. The reversal of 213223111207 is 702111322312.
213223111207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213223111207 - 231 = 211075627559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213223111307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106611555603 + 106611555604.
It is an arithmetic number, because the mean of its divisors is an integer number (106611555604).
Almost surely, 2213223111207 is an apocalyptic number.
213223111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
213223111207 is an equidigital number, since it uses as much as digits as its factorization.
213223111207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 213223111207 its reverse (702111322312), we get a palindrome (915334433519).
The spelling of 213223111207 in words is "two hundred thirteen billion, two hundred twenty-three million, one hundred eleven thousand, two hundred seven".
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