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213231004117 is a prime number
BaseRepresentation
bin1100011010010110001…
…1101110100111010101
3202101101102202100000221
43012211203232213111
511443144114112432
6241542412234341
721256030426015
oct3064543564725
9671342670027
10213231004117
118248138544a
12353aa76b9b1
13171525121b1
14a46b3bdc45
15582ed06b97
hex31a58ee9d5

213231004117 has 2 divisors, whose sum is σ = 213231004118. Its totient is φ = 213231004116.

The previous prime is 213231004099. The next prime is 213231004121. The reversal of 213231004117 is 711400132312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 162603304081 + 50627700036 = 403241^2 + 225006^2 .

It is a cyclic number.

It is not a de Polignac number, because 213231004117 - 211 = 213231002069 is a prime.

It is a super-2 number, since 2×2132310041172 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213231004091 and 213231004100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213231004127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106615502058 + 106615502059.

It is an arithmetic number, because the mean of its divisors is an integer number (106615502059).

Almost surely, 2213231004117 is an apocalyptic number.

It is an amenable number.

213231004117 is a deficient number, since it is larger than the sum of its proper divisors (1).

213231004117 is an equidigital number, since it uses as much as digits as its factorization.

213231004117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 213231004117 its reverse (711400132312), we get a palindrome (924631136429).

The spelling of 213231004117 in words is "two hundred thirteen billion, two hundred thirty-one million, four thousand, one hundred seventeen".