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213300122111431 is a prime number
BaseRepresentation
bin110000011111111011001110…
…000000100100110111000111
31000222020021220020211111222121
4300133323032000210313013
5210424202122230031211
62033352420124310411
762633265604045555
oct6037731600446707
91028207806744877
10213300122111431
1161a6708a233483
121bb0abab3a2407
13920316615bb84
143a95ad1096bd5
15199d65b9a6271
hexc1fece024dc7

213300122111431 has 2 divisors, whose sum is σ = 213300122111432. Its totient is φ = 213300122111430.

The previous prime is 213300122111381. The next prime is 213300122111473. The reversal of 213300122111431 is 134111221003312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213300122111431 - 211 = 213300122109383 is a prime.

It is a super-2 number, since 2×2133001221114312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213300122111396 and 213300122111405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213300122211431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106650061055715 + 106650061055716.

It is an arithmetic number, because the mean of its divisors is an integer number (106650061055716).

Almost surely, 2213300122111431 is an apocalyptic number.

213300122111431 is a deficient number, since it is larger than the sum of its proper divisors (1).

213300122111431 is an equidigital number, since it uses as much as digits as its factorization.

213300122111431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 213300122111431 its reverse (134111221003312), we get a palindrome (347411343114743).

The spelling of 213300122111431 in words is "two hundred thirteen trillion, three hundred billion, one hundred twenty-two million, one hundred eleven thousand, four hundred thirty-one".