Search a number
-
+
21330133043140 = 225171571897321061
BaseRepresentation
bin1001101100110010011110…
…00000001100011111000100
32210112010210122110011010201
410312121033000030133010
510243433103024340030
6113210532225300244
74331023403236105
oct466311700143704
983463718404121
1021330133043140
116884071033569
122485b0a494684
13bb95661b5bcc
1453a5537a43ac
1526eca44152ca
hex13664f00c7c4

21330133043140 has 96 divisors (see below), whose sum is σ = 47735050585824. Its totient is φ = 7978220789760.

The previous prime is 21330133043119. The next prime is 21330133043183. The reversal of 21330133043140 is 4134033103312.

It can be written as a sum of positive squares in 16 ways, for example, as 447938395524 + 20882194647616 = 669282^2 + 4569704^2 .

It is a junction number, because it is equal to n+sod(n) for n = 21330133043099 and 21330133043108.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1012768210 + ... + 1012789270.

It is an arithmetic number, because the mean of its divisors is an integer number (497240110269).

Almost surely, 221330133043140 is an apocalyptic number.

21330133043140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21330133043140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23867525292912).

21330133043140 is an abundant number, since it is smaller than the sum of its proper divisors (26404917542684).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21330133043140 is a wasteful number, since it uses less digits than its factorization.

21330133043140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40217 (or 40215 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 21330133043140 its reverse (4134033103312), we get a palindrome (25464166146452).

It can be divided in two parts, 2133013 and 3043140, that added together give a triangular number (5176153 = T3217).

The spelling of 21330133043140 in words is "twenty-one trillion, three hundred thirty billion, one hundred thirty-three million, forty-three thousand, one hundred forty".

Divisors: 1 2 4 5 10 17 20 34 68 85 157 170 314 340 628 785 1570 2669 3140 5338 10676 13345 18973 21061 26690 37946 42122 53380 75892 84244 94865 105305 189730 210610 322541 358037 379460 421220 645082 716074 1290164 1432148 1612705 1790185 2978761 3225410 3306577 3580370 5957522 6450820 6613154 7160740 11915044 13226308 14893805 16532885 29787610 33065770 50638937 56211809 59575220 66131540 101277874 112423618 202555748 224847236 253194685 281059045 399590353 506389370 562118090 799180706 1012778740 1124236180 1598361412 1997951765 3995903530 6793036001 7991807060 13586072002 27172144004 33965180005 62735685421 67930360010 125471370842 135860720020 250942741684 313678427105 627356854210 1066506652157 1254713708420 2133013304314 4266026608628 5332533260785 10665066521570 21330133043140