Base | Representation |
---|---|
bin | 1001101100110100010010… |
… | …10011001111001001100000 |
3 | 2210112020022210212021011220 |
4 | 10312122021103033021200 |
5 | 10243442103421111222 |
6 | 113211213244535040 |
7 | 4331056550552460 |
oct | 466321123171140 |
9 | 83466283767156 |
10 | 21331111113312 |
11 | 6884523139120 |
12 | 2486141b51480 |
13 | bb9690a15460 |
14 | 53a607643ba0 |
15 | 26ed10213b5c |
hex | 1366894cf260 |
21331111113312 has 1536 divisors, whose sum is σ = 79017330180096. Its totient is φ = 4861181952000.
The previous prime is 21331111113289. The next prime is 21331111113391.
21331111113312 is nontrivially palindromic in base 10.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 35971519288 + ... + 35971519880.
It is an arithmetic number, because the mean of its divisors is an integer number (51443574336).
Almost surely, 221331111113312 is an apocalyptic number.
21331111113312 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 21331111113312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (39508665090048).
21331111113312 is an abundant number, since it is smaller than the sum of its proper divisors (57686219066784).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21331111113312 is a wasteful number, since it uses less digits than its factorization.
21331111113312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 892 (or 884 counting only the distinct ones).
The product of its digits is 324, while the sum is 24.
It can be divided in two parts, 2133111 and 1113312, that added together give a palindrome (3246423).
The spelling of 21331111113312 in words is "twenty-one trillion, three hundred thirty-one billion, one hundred eleven million, one hundred thirteen thousand, three hundred twelve".
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