Base | Representation |
---|---|
bin | 1100011010101001100… |
… | …1001101011111101100 |
3 | 202101121002102010002002 |
4 | 3012222121031133230 |
5 | 11443330401224400 |
6 | 241554431151432 |
7 | 21261034133453 |
oct | 3065231153754 |
9 | 671532363062 |
10 | 213312133100 |
11 | 825131578a0 |
12 | 35411975578 |
13 | 17166279401 |
14 | a47809bb9a |
15 | 5836eceed5 |
hex | 31aa64d7ec |
213312133100 has 144 divisors (see below), whose sum is σ = 513096909696. Its totient is φ = 76326912000.
The previous prime is 213312133051. The next prime is 213312133103. The reversal of 213312133100 is 1331213312.
It is a super-2 number, since 2×2133121331002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (213312133103) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23459555 + ... + 23468645.
It is an arithmetic number, because the mean of its divisors is an integer number (3563172984).
Almost surely, 2213312133100 is an apocalyptic number.
213312133100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 213312133100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (256548454848).
213312133100 is an abundant number, since it is smaller than the sum of its proper divisors (299784776596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213312133100 is a wasteful number, since it uses less digits than its factorization.
213312133100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9456 (or 9449 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 213312133100 its reverse (1331213312), we get a palindrome (214643346412).
It can be divided in two parts, 21331 and 2133100, that multiplied together give a square (45501156100 = 2133102).
The spelling of 213312133100 in words is "two hundred thirteen billion, three hundred twelve million, one hundred thirty-three thousand, one hundred".
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