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213314011310130 = 2357110467043671
BaseRepresentation
bin110000100000001000001001…
…110111101010100000110010
31000222021121202012210220202020
4300200020021313222200302
5210424414043343411010
62033403034242132310
762634300025224333
oct6040101167524062
91028247665726666
10213314011310130
1161a71a67332a95
121bb11826951096
13920456a814a43
143a9664b96a28a
15199dbc0eee470
hexc20209dea832

213314011310130 has 16 divisors (see below), whose sum is σ = 511953627144384. Its totient is φ = 56883736349360.

The previous prime is 213314011310129. The next prime is 213314011310173. The reversal of 213314011310130 is 31013110413312.

It is a self number, because there is not a number n which added to its sum of digits gives 213314011310130.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3555233521806 + ... + 3555233521865.

It is an arithmetic number, because the mean of its divisors is an integer number (31997101696524).

Almost surely, 2213314011310130 is an apocalyptic number.

213314011310130 is an abundant number, since it is smaller than the sum of its proper divisors (298639615834254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213314011310130 is a wasteful number, since it uses less digits than its factorization.

213314011310130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7110467043681.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 213314011310130 its reverse (31013110413312), we get a palindrome (244327121723442).

The spelling of 213314011310130 in words is "two hundred thirteen trillion, three hundred fourteen billion, eleven million, three hundred ten thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 7110467043671 14220934087342 21331401131013 35552335218355 42662802262026 71104670436710 106657005655065 213314011310130