Base | Representation |
---|---|
bin | 11111000010110011111… |
… | …001101001011101010101 |
3 | 21112221110212201211000221 |
4 | 133002303321221131111 |
5 | 234423020413400001 |
6 | 4312011250234341 |
7 | 310061464625041 |
oct | 37026371513525 |
9 | 7487425654027 |
10 | 2133322012501 |
11 | 75281172a099 |
12 | 2a55512859b1 |
13 | 12622c757674 |
14 | 75379225021 |
15 | 3a75c7e11a1 |
hex | 1f0b3e69755 |
2133322012501 has 2 divisors, whose sum is σ = 2133322012502. Its totient is φ = 2133322012500.
The previous prime is 2133322012477. The next prime is 2133322012513. The reversal of 2133322012501 is 1052102233312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1588381296100 + 544940716401 = 1260310^2 + 738201^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2133322012501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2133322012571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066661006250 + 1066661006251.
It is an arithmetic number, because the mean of its divisors is an integer number (1066661006251).
Almost surely, 22133322012501 is an apocalyptic number.
It is an amenable number.
2133322012501 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133322012501 is an equidigital number, since it uses as much as digits as its factorization.
2133322012501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 2133322012501 its reverse (1052102233312), we get a palindrome (3185424245813).
The spelling of 2133322012501 in words is "two trillion, one hundred thirty-three billion, three hundred twenty-two million, twelve thousand, five hundred one".
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