Base | Representation |
---|---|
bin | 11111000010110100100… |
… | …111110101101011010101 |
3 | 21112221111201112000000021 |
4 | 133002310213311223111 |
5 | 234423032013334143 |
6 | 4312012401545141 |
7 | 310062002556223 |
oct | 37026447655325 |
9 | 7487451460007 |
10 | 2133334121173 |
11 | 75281854a562 |
12 | 2a55553451b1 |
13 | 126232106c68 |
14 | 7537aa97b13 |
15 | 3a75d8d3ced |
hex | 1f0b49f5ad5 |
2133334121173 has 2 divisors, whose sum is σ = 2133334121174. Its totient is φ = 2133334121172.
The previous prime is 2133334121167. The next prime is 2133334121213. The reversal of 2133334121173 is 3711214333312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1743250183684 + 390083937489 = 1320322^2 + 624567^2 .
It is a cyclic number.
It is not a de Polignac number, because 2133334121173 - 25 = 2133334121141 is a prime.
It is a super-2 number, since 2×21333341211732 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2133334121273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066667060586 + 1066667060587.
It is an arithmetic number, because the mean of its divisors is an integer number (1066667060587).
Almost surely, 22133334121173 is an apocalyptic number.
It is an amenable number.
2133334121173 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133334121173 is an equidigital number, since it uses as much as digits as its factorization.
2133334121173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27216, while the sum is 34.
Adding to 2133334121173 its reverse (3711214333312), we get a palindrome (5844548454485).
The spelling of 2133334121173 in words is "two trillion, one hundred thirty-three billion, three hundred thirty-four million, one hundred twenty-one thousand, one hundred seventy-three".
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