Base | Representation |
---|---|
bin | 1100011011000010111… |
… | …0101000110101011111 |
3 | 202101212111101201020202 |
4 | 3012300232220311133 |
5 | 11444040103212112 |
6 | 242013145134115 |
7 | 21263464403543 |
oct | 3066056506537 |
9 | 671774351222 |
10 | 213418413407 |
11 | 82568148861 |
12 | 3544148a33b |
13 | 171822ab674 |
14 | a488245a23 |
15 | 58414c56c2 |
hex | 31b0ba8d5f |
213418413407 has 2 divisors, whose sum is σ = 213418413408. Its totient is φ = 213418413406.
The previous prime is 213418413371. The next prime is 213418413433. The reversal of 213418413407 is 704314814312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213418413407 - 234 = 196238544223 is a prime.
It is a super-3 number, since 3×2134184134073 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213418413707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106709206703 + 106709206704.
It is an arithmetic number, because the mean of its divisors is an integer number (106709206704).
Almost surely, 2213418413407 is an apocalyptic number.
213418413407 is a deficient number, since it is larger than the sum of its proper divisors (1).
213418413407 is an equidigital number, since it uses as much as digits as its factorization.
213418413407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 38.
The spelling of 213418413407 in words is "two hundred thirteen billion, four hundred eighteen million, four hundred thirteen thousand, four hundred seven".
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