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21342044231 is a prime number
BaseRepresentation
bin10011111000000101…
…011100000001000111
32001002100211011211122
4103320011130001013
5322202030403411
613445430024155
71353606245204
oct237005340107
961070734748
1021342044231
119062033792
1241774a805b
132021743a51
14106662ccab
1584d9b39db
hex4f815c047

21342044231 has 2 divisors, whose sum is σ = 21342044232. Its totient is φ = 21342044230.

The previous prime is 21342044201. The next prime is 21342044233. The reversal of 21342044231 is 13244024312.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21342044231 is a prime.

It is a super-2 number, since 2×213420442312 (a number of 21 digits) contains 22 as substring.

Together with 21342044233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21342044231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21342044233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10671022115 + 10671022116.

It is an arithmetic number, because the mean of its divisors is an integer number (10671022116).

Almost surely, 221342044231 is an apocalyptic number.

21342044231 is a deficient number, since it is larger than the sum of its proper divisors (1).

21342044231 is an equidigital number, since it uses as much as digits as its factorization.

21342044231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 21342044231 its reverse (13244024312), we get a palindrome (34586068543).

The spelling of 21342044231 in words is "twenty-one billion, three hundred forty-two million, forty-four thousand, two hundred thirty-one".