Base | Representation |
---|---|
bin | 11111000011101010110… |
… | …010111110111100001111 |
3 | 21120000212001202110100002 |
4 | 133003222302332330033 |
5 | 234431412202343432 |
6 | 4312242510354515 |
7 | 310123350165614 |
oct | 37035262767417 |
9 | 7500761673302 |
10 | 2134243012367 |
11 | 7531445a4a04 |
12 | 2a57697bba3b |
13 | 1263484c45bb |
14 | 7542568a50b |
15 | 3a7b35b9e62 |
hex | 1f0eacbef0f |
2134243012367 has 2 divisors, whose sum is σ = 2134243012368. Its totient is φ = 2134243012366.
The previous prime is 2134243012261. The next prime is 2134243012393. The reversal of 2134243012367 is 7632103424312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2134243012367 - 218 = 2134242750223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2134243012367.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2134243012667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067121506183 + 1067121506184.
It is an arithmetic number, because the mean of its divisors is an integer number (1067121506184).
Almost surely, 22134243012367 is an apocalyptic number.
2134243012367 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134243012367 is an equidigital number, since it uses as much as digits as its factorization.
2134243012367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 2134243012367 its reverse (7632103424312), we get a palindrome (9766346436679).
The spelling of 2134243012367 in words is "two trillion, one hundred thirty-four billion, two hundred forty-three million, twelve thousand, three hundred sixty-seven".
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