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21354276737 is a prime number
BaseRepresentation
bin10011111000110100…
…000110011110000001
32001010012211122200102
4103320310012132001
5322213143323422
613450544132145
71354115233403
oct237064063601
961105748612
1021354276737
119068a291a2
12417b607055
132024137811
1410680d4b73
1584eacd192
hex4f8d06781

21354276737 has 2 divisors, whose sum is σ = 21354276738. Its totient is φ = 21354276736.

The previous prime is 21354276709. The next prime is 21354276739. The reversal of 21354276737 is 73767245312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19915136641 + 1439140096 = 141121^2 + 37936^2 .

It is a cyclic number.

It is not a de Polignac number, because 21354276737 - 214 = 21354260353 is a prime.

Together with 21354276739, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21354276691 and 21354276700.

It is not a weakly prime, because it can be changed into another prime (21354276739) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10677138368 + 10677138369.

It is an arithmetic number, because the mean of its divisors is an integer number (10677138369).

Almost surely, 221354276737 is an apocalyptic number.

It is an amenable number.

21354276737 is a deficient number, since it is larger than the sum of its proper divisors (1).

21354276737 is an equidigital number, since it uses as much as digits as its factorization.

21354276737 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1481760, while the sum is 47.

The spelling of 21354276737 in words is "twenty-one billion, three hundred fifty-four million, two hundred seventy-six thousand, seven hundred thirty-seven".