214001113 has 2 divisors, whose sum is σ = 214001114. Its totient is φ = 214001112.

The previous prime is 214001111. The next prime is 214001119. The reversal of 214001113 is 311100412.

214001113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 213949129 + 51984 = 14627^2 + 228^2 .

It is a cyclic number.

It is not a de Polignac number, because 214001113 - 2¹ = 214001111 is a prime.

Together with 214001111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 214001093 and 214001102.

It is not a weakly prime, because it can be changed into another prime (214001111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107000556 + 107000557.

It is an arithmetic number, because the mean of its divisors is an integer number (107000557).

Almost surely, 2^214001113 is an apocalyptic number.

It is an amenable number.

214001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

214001113 is an equidigital number, since it uses as much as digits as its factorization.

214001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 214001113 is about 14628.7768798352. The cubic root of 214001113 is about 598.1434399368.

Adding to 214001113 its reverse (311100412), we get a palindrome (525101525).

The spelling of 214001113 in words is "two hundred fourteen million, one thousand, one hundred thirteen".