21401141999 has 2 divisors, whose sum is σ = 21401142000. Its totient is φ = 21401141998.

The previous prime is 21401141987. The next prime is 21401142001. The reversal of 21401141999 is 99914110412.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21401141999 is a prime.

It is a super-2 number, since 2×21401141999² (a number of 21 digits) contains 22 as substring.

Together with 21401142001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21401141969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700570999 + 10700571000.

It is an arithmetic number, because the mean of its divisors is an integer number (10700571000).

Almost surely, 2^21401141999 is an apocalyptic number.

21401141999 is a deficient number, since it is larger than the sum of its proper divisors (1).

21401141999 is an equidigital number, since it uses as much as digits as its factorization.

21401141999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 41.

The spelling of 21401141999 in words is "twenty-one billion, four hundred one million, one hundred forty-one thousand, nine hundred ninety-nine".