Base | Representation |
---|---|
bin | 1001101110110111001101… |
… | …10111101000111110010111 |
3 | 2210202221202101120201010121 |
4 | 10313123212313220332113 |
5 | 10301120032001222403 |
6 | 113303400112332411 |
7 | 4336125440010613 |
oct | 467334667507627 |
9 | 83687671521117 |
10 | 21401400414103 |
11 | 6901312667156 |
12 | 2497899844107 |
13 | bc31b30829b8 |
14 | 53db94846343 |
15 | 271a75e1d3bd |
hex | 1376e6de8f97 |
21401400414103 has 2 divisors, whose sum is σ = 21401400414104. Its totient is φ = 21401400414102.
The previous prime is 21401400414047. The next prime is 21401400414127. The reversal of 21401400414103 is 30141400410412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21401400414103 - 225 = 21401366859671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21401400414403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700700207051 + 10700700207052.
It is an arithmetic number, because the mean of its divisors is an integer number (10700700207052).
Almost surely, 221401400414103 is an apocalyptic number.
21401400414103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21401400414103 is an equidigital number, since it uses as much as digits as its factorization.
21401400414103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 21401400414103 its reverse (30141400410412), we get a palindrome (51542800824515).
The spelling of 21401400414103 in words is "twenty-one trillion, four hundred one billion, four hundred million, four hundred fourteen thousand, one hundred three".
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