Base | Representation |
---|---|
bin | 11111001001010110011… |
… | …101111110010100001000 |
3 | 21120121121021121122100001 |
4 | 133021112131332110020 |
5 | 240031411132131100 |
6 | 4315132144452344 |
7 | 310430505214156 |
oct | 37112635762410 |
9 | 7517537548301 |
10 | 2140344411400 |
11 | 755795692348 |
12 | 2a699101a0b4 |
13 | 126aab5a38a0 |
14 | 75843b323d6 |
15 | 3aa1e081d6a |
hex | 1f25677e508 |
2140344411400 has 96 divisors (see below), whose sum is σ = 5359491345600. Its totient is φ = 790222291200.
The previous prime is 2140344411371. The next prime is 2140344411419. The reversal of 2140344411400 is 41144430412.
It is a super-2 number, since 2×21403444114002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 51956011 + ... + 51997189.
It is an arithmetic number, because the mean of its divisors is an integer number (55828034850).
Almost surely, 22140344411400 is an apocalyptic number.
2140344411400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2140344411400 is an abundant number, since it is smaller than the sum of its proper divisors (3219146934200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2140344411400 is a wasteful number, since it uses less digits than its factorization.
2140344411400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61199 (or 61190 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 2140344411400 its reverse (41144430412), we get a palindrome (2181488841812).
The spelling of 2140344411400 in words is "two trillion, one hundred forty billion, three hundred forty-four million, four hundred eleven thousand, four hundred".
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