Base | Representation |
---|---|
bin | 1001101110111110100000… |
… | …00001101110101000110111 |
3 | 2210210022212000012111002112 |
4 | 10313133100001232220313 |
5 | 10301201034402300241 |
6 | 113305244210401235 |
7 | 4336324406141633 |
oct | 467372001565067 |
9 | 83708760174075 |
10 | 21405312150071 |
11 | 6902a3a7452a3 |
12 | 24985ab89021b |
13 | bc368760c675 |
14 | 540046181dc3 |
15 | 271c0455b1eb |
hex | 1377d006ea37 |
21405312150071 has 2 divisors, whose sum is σ = 21405312150072. Its totient is φ = 21405312150070.
The previous prime is 21405312149983. The next prime is 21405312150077. The reversal of 21405312150071 is 17005121350412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21405312150071 - 214 = 21405312133687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21405312150077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10702656075035 + 10702656075036.
It is an arithmetic number, because the mean of its divisors is an integer number (10702656075036).
Almost surely, 221405312150071 is an apocalyptic number.
21405312150071 is a deficient number, since it is larger than the sum of its proper divisors (1).
21405312150071 is an equidigital number, since it uses as much as digits as its factorization.
21405312150071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 32.
The spelling of 21405312150071 in words is "twenty-one trillion, four hundred five billion, three hundred twelve million, one hundred fifty thousand, seventy-one".
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