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21410544437 is a prime number
BaseRepresentation
bin10011111100001010…
…101111101100110101
32001021010201100110022
4103330022233230311
5322322044410222
613500314134525
71355400424232
oct237412575465
961233640408
1021410544437
11909776aa27
124196421445
1320329a8a09
141071780789
158549e5042
hex4fc2afb35

21410544437 has 2 divisors, whose sum is σ = 21410544438. Its totient is φ = 21410544436.

The previous prime is 21410544377. The next prime is 21410544439. The reversal of 21410544437 is 73444501412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16291714321 + 5118830116 = 127639^2 + 71546^2 .

It is a cyclic number.

It is not a de Polignac number, because 21410544437 - 214 = 21410528053 is a prime.

It is a super-2 number, since 2×214105444372 (a number of 21 digits) contains 22 as substring.

Together with 21410544439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21410544397 and 21410544406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21410544439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10705272218 + 10705272219.

It is an arithmetic number, because the mean of its divisors is an integer number (10705272219).

Almost surely, 221410544437 is an apocalyptic number.

It is an amenable number.

21410544437 is a deficient number, since it is larger than the sum of its proper divisors (1).

21410544437 is an equidigital number, since it uses as much as digits as its factorization.

21410544437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 53760, while the sum is 35.

The spelling of 21410544437 in words is "twenty-one billion, four hundred ten million, five hundred forty-four thousand, four hundred thirty-seven".