Base | Representation |
---|---|
bin | 11111001010001011111… |
… | …111100101010011011101 |
3 | 21120200220212100220201202 |
4 | 133022023333211103131 |
5 | 240040231024224201 |
6 | 4315401224045245 |
7 | 310461661134344 |
oct | 37121377452335 |
9 | 7520825326652 |
10 | 2141242414301 |
11 | 756106580201 |
12 | 2a6ba1903825 |
13 | 126bc264b253 |
14 | 758cb0ccb5b |
15 | 3aa72d16c6b |
hex | 1f28bfe54dd |
2141242414301 has 2 divisors, whose sum is σ = 2141242414302. Its totient is φ = 2141242414300.
The previous prime is 2141242414277. The next prime is 2141242414303. The reversal of 2141242414301 is 1034142421412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2049266688676 + 91975725625 = 1431526^2 + 303275^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2141242414301 is a prime.
Together with 2141242414303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2141242414303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070621207150 + 1070621207151.
It is an arithmetic number, because the mean of its divisors is an integer number (1070621207151).
Almost surely, 22141242414301 is an apocalyptic number.
It is an amenable number.
2141242414301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141242414301 is an equidigital number, since it uses as much as digits as its factorization.
2141242414301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 2141242414301 its reverse (1034142421412), we get a palindrome (3175384835713).
The spelling of 2141242414301 in words is "two trillion, one hundred forty-one billion, two hundred forty-two million, four hundred fourteen thousand, three hundred one".
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