Search a number
-
+
214131433127 is a prime number
BaseRepresentation
bin1100011101101100111…
…0100101111010100111
3202110201012001212102112
43013123032211322213
512002020121330002
6242212015431235
721320243102333
oct3073316457247
9673635055375
10214131433127
11828a3680057
123560022551b
1317266c28c21
14a514c0c7c3
155883dba852
hex31db3a5ea7

214131433127 has 2 divisors, whose sum is σ = 214131433128. Its totient is φ = 214131433126.

The previous prime is 214131433069. The next prime is 214131433223. The reversal of 214131433127 is 721334131412.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 214131433127 - 28 = 214131432871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214131433093 and 214131433102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214131463127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107065716563 + 107065716564.

It is an arithmetic number, because the mean of its divisors is an integer number (107065716564).

Almost surely, 2214131433127 is an apocalyptic number.

214131433127 is a deficient number, since it is larger than the sum of its proper divisors (1).

214131433127 is an equidigital number, since it uses as much as digits as its factorization.

214131433127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12096, while the sum is 32.

Adding to 214131433127 its reverse (721334131412), we get a palindrome (935465564539).

The spelling of 214131433127 in words is "two hundred fourteen billion, one hundred thirty-one million, four hundred thirty-three thousand, one hundred twenty-seven".