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2141340204013 is a prime number
BaseRepresentation
bin11111001010010001110…
…100100111101111101101
321120201011200101010222221
4133022101310213233231
5240040431043012023
64315415040035341
7310464256262503
oct37122164475755
97521150333887
102141340204013
117561567a204a
122a700a602b51
13126c0999999a
14758da0a6673
153aa7b6d185d
hex1f291d27bed

2141340204013 has 2 divisors, whose sum is σ = 2141340204014. Its totient is φ = 2141340204012.

The previous prime is 2141340204001. The next prime is 2141340204067. The reversal of 2141340204013 is 3104020431412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1782110191849 + 359230012164 = 1334957^2 + 599358^2 .

It is a cyclic number.

It is not a de Polignac number, because 2141340204013 - 221 = 2141338106861 is a prime.

It is a super-2 number, since 2×21413402040132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2141340204413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070670102006 + 1070670102007.

It is an arithmetic number, because the mean of its divisors is an integer number (1070670102007).

Almost surely, 22141340204013 is an apocalyptic number.

It is an amenable number.

2141340204013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2141340204013 is an equidigital number, since it uses as much as digits as its factorization.

2141340204013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2141340204013 its reverse (3104020431412), we get a palindrome (5245360635425).

The spelling of 2141340204013 in words is "two trillion, one hundred forty-one billion, three hundred forty million, two hundred four thousand, thirteen".